C语言 这式子该怎么写 includeincludevoid main(){float a=0，x=0；double y=0；scanf(\"%f%f\"，&a，&x)；y=pow(a，5)+sin(a*x)+log(a+x)+exp(a*x)；printf(\"%f\\n\"，y)；}
c语言基础 includedefine N 50voidquestion1(){int num[N]；50个数字的数组int i=0；int flag=0；for；i；i+){scanf(\"%d\"，&num[i])；if(num[i]%2。0)num[i]=-1；}for(i=0；i；i+){if(num[i]。1){printf(\"%d\"，num[i])；flag+；if(flag%10=0)printf(\"\\n\")；}}}voidquestion2(){int num；printf(\"a number：\")；scanf(\"%d\"，&num)；if(num%5=0&num%7=0)printf(\"yes\\n\")；elseprintf(\"no\\n\")；}voidquestion3(){int c；printf(\"input：\")；scanf(\"%d\"，&c)；if((c>；=65&c)|(c>；=97&c))printf(\"letter：%c ascii：%d\\n\"，c，c)；elseif(c>；=0&c)printf(\"a number：%d\\n\"，c)；elseprintf(\"error\\n\")；}voidquestion4(){int a，b，c；printf(\"input a、b、c：\\n\")；scanf(\"%d%d%d\"，&a，&b，&c)；printf(\"min number is：%d\\n\"，a<；b？(a)：(b)？b：c)；}voidquestion5(){int num[10]；int i=0；int sum=0；int flag=0；for；i；i+){scanf(\"%d\"，&num[i])；if(num[i]){sum+num[i]；flag+；}}printf(\"sum：%d number：%d\\n\"，sum，flag)；}int main(void){question1()；question2()；question3()；question4()；question5()；return 0；}应该差不多
简单的C语言求解 includeint main(){int a，b，c，sum；scanf(\"%d%d%d\"，&a，&b，&c)；sum=a+b+c；printf(\"%d%.3lf\\n\"，sum，sum*1.0/3)；return 0；}includeincludedefine PI acos(-1.0)int main(){double a，b，x；scanf(\"%lf%lf%lf\"，&a，&b，&x)；printf(\"%lf\\n\"，0.5*a*b*sin(x/180*PI))；return 0；}
