SQL语句查询 如何删除重复多余的数据
一个表中有重复记录如何用SQL语句查询出来。。。？ select*from tablename where 重复字段1 in(select 重复字段1 from tablename group by 重复字段1，重复字段2 having count(*)>；1)。SQL重复记录查询方法：1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断select*from peoplewhere peopleId in(select peopleId from people group by peopleId having count(peopleId)>；1)2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录delete from peoplewhere peopleId in(select peopleId from people group by peopleId having count(peopleId)>；1)and rowid not in(select min(rowid)from people group by peopleId having count(peopleId)>；1)3、查找表中多余的重复记录（多个字段）select*from vitae awhere(a.peopleId，a.seq)in(select peopleId，seq from vitae group by peopleId，seq having
表中有重复的记录，写SQL语句筛选掉重复的记录 不能使用Group by.请问高手怎么写啊？ group by 是分类汇总 会自动提取不重复值的
SQL查询中如何剔除重复 1，存2113在两条完全相同的纪录这是5261最简单的一种情况，用关4102键字distinct就可以去掉example：select distinct*from table(表名1653)where(条件)2，存在部分字段相同的纪录（有主键id即唯一键）如果是这种情况的话用distinct是过滤不了的，这就要用到主键id的唯一性特点及group by分组example：select*from table where id in(select max(id)from table group by[去除重复的字段名列表，.])3，没有唯一键IDexample：select identity(int1，1)as id，*into newtable(临时表)from tableselect*from newtable where id in(select max(id)from newtable group by[去除重复的字段名列表，.])drop table newtable扩展资料1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断select*from peoplewhere peopleId in(select peopleId from people group by peopleId having count(peopleId)>；1)2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录delete from peoplewhere peopleId in(select peopleId from people group by peopleId having count(peopleId)>；1)and rowid not in(select min。
一个表中有重复记录如何用SQL语句查询出来？ SQL重复记录查询方法：1、查找表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断2、删除表中多余的重复记录，重复记录是根据单个字段（peopleId）来判断，只留有rowid最小的记录3、查找表中多余的重复记录（多个字段）
