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下列叙述正确的是 co是二级能源
CO、H (1)①反应热=反应物总键能-生成物总键能,则:CO(g)+2H2(g)?CH3OH(g)的△H=1076kJmol+2×436kJmol-3×408kJmol-351kJmol-463kJmol=-90kJmol,故答案为:-9...
CO、H (1)①反应热=反应物总键能-生成物总键能,则:CO(g)+2H2(g)?CH3OH(g)的△H=1076kJmol+2×436kJmol-3×408kJmol-351kJmol-463kJmol=-90kJmol,故答案为:-9...