计算某年某月有多少天 c语言 给伪码days[2][12]={{31，28，31，30，31，30，31，31，30，31，30，31}，{31，29，31，30，31，30，31，31，30，31，30，31}}int year(int num)；判断平闰年int y=year(某年)？0：1；int i；累加器int month，day；年月for(i=0；i；i+){day+month[y][i]；}输出day；
编写计算莫年某月有多少天用C语言 include<；stdio.h>；int main(void){int year，mouth；printf(\"Input year：\")；scanf(\"%d\"，&year)；printf(\"Input mouth：\")；scanf(\"%d\"，&mouth)；switch(mouth){case 1：case 3：case 5：case 7：case 8：case 10：case 12：printf(\"There are 31 days in%d mouth.\\n\"，mouth)；break；case 4：case 6：case 9：case 11：printf(\"There are 30 days in%d mouth.\\n\"，mouth)；break；case 2：if((year%400=0)|(year%4=0&year%100。0))printf(\"There are 29 days in%d mouth.\\n\"，mouth)；elseprintf(\"There are 28 days in%d mouth.\\n\"，mouth)；break；default：printf(\"Input error mouth.\\n\")；break；} return 0；}
关于C语言简易编程 计算某年某月多少天 |#includevoid main(){int year，month；printf(\"\\n Please input year：\\n\")；scanf(\"%d\"，&year)；printf(\"enter month：\\n\")；scanf(\"%d\"，&month)；if(year%4=0){if(month=2)printf(\"\\n day=d\"，29)；else{if(month=4|month=6|month=9|month=11)printf(\"\\n day=d\"，30)；elseprintf(\"\\n day=d\"，31)；}}else{if(month=2)printf(\"\\n day=d\"，28)；else{if(month=4|month=6|month=9|month=11)printf(\"\\n day=d\"，30)；elseprintf(\"\\n day=d\"，31)；}}}只是把输入部分改了 输出结果是对的 还有你的32313133353236313431303231363533e58685e5aeb931333330356263判断闰年的方法有误应该是if(i%4=0&i%100。0|i%400=0)则i为闰年
