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从湖水中取出深层水,其PH=7.0,含溶解氧质量浓度为0.32mgL,请计算pE和Eh.如何做?公式是什么?答案是pE=13.2,Eh=0.78V. 从湖水中取得深层水水样 其ph=7

2021-04-09知识4

13、从湖水中取出深层水其PH=7.00,含氧浓度0.32mg/L,计算PE值是多少? pe=13.2,Eh=7.8

求翻译一篇,200分悬赏。不要翻译软件的哦~ 修正版:光合细菌生长及氮磷同化率影响因素的研究The Research on the Growth of Photosynthetic Bacteria and the Contributory Factors to the Assimilation Rate of Nitrogen and Phosphorus摘要:从湖水表层水样中筛选出纯净的光合细菌菌种。通过对光合细菌中的沼泽红假单胞菌在不同成分培养基学生长情况研究,结果表明该菌生长的最适pH值为6.5—7.5,最适温度在25℃—35℃范围之间,最适合纯种菌液接种量为10%,盐度低于2 g?L-1后,OD值逐渐下降;氮磷同化率与之对应。Abstract:Pure strains of photosynthetic bacteria(PSB)were isolated from lake surface water samples.Through the studying of the growth conditions of rhodopseudomonas palustris in the PSB under different compositions of culture medium,the results showed that the most suitable pH value for the growth of the bacteria was 6.5—7.5,the most suitable temperature was between the range of 25℃—35℃,the most suitable pure breed bacteria liquid inoculation amount was 10%,OD value was dropping gradually afters alinity was below 2 g?L-1,and 。

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#从湖水中取得深层水水样 其ph=7

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