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perl求余数 perl 字符串与二进制数字

2021-04-09知识11

对于各进制之间的转换有什么好方法吗? 也就是二进制、八进制、十进制、十六进制之间的转换,书本上的觉得好麻烦啊(没那么聪明).(不考…

编程实现产生余数相同的随机数 subrand100{my($max,$min)$cnt=0;if($max-$min>;300&$min>;0){while($cnt){my$num=$min+rand($max-$min);if(($num%3=1){,$num;cnt+;}}} }(1000,300);

1994个8除以26余数是几 写了一小段辅助程序,终于解决了。答案为10。因为每增加一个8,即相当于前N-1个8除以26的余数 乘以10加上8 再跟26算余数。e799bee5baa6e59b9ee7ad9431333332613635简而言之,a[n]=(10*a[n-1]+8)%26,a[1]=8。当有1,2,3,4。个8时,余数为8,10,4,22,20,0的循环。所以,1994/6 余2,1994个8除以26余数,即为 10。附上程序(perl)while(){chomp;my($a,$b)=split;print\"$a divided by$b remains\".$a%$b.\"\\n;}运行结果:C:\\Ren Shirui\\Perl>;perl testStrict.pl8 268 divided by 26 remains 888 2688 divided by 26 remains 10888 26888 divided by 26 remains 48888 268888 divided by 26 remains 2288888 2688888 divided by 26 remains 20888888 26888888 divided by 26 remains 08888888 268888888 divided by 26 remains 888888888 2688888888 divided by 26 remains 10888888888 26888888888 divided by 26 remains 4

#perl求余数

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