c语言中如何用指向函数求正余弦的值？ include<；stdio.h>；#include<；math.h>；void main(){ double x，term，sum，x2；int i；printf(\"请输入弧度x的值：\")；scanf(\"%lf\"，&x)；x2=x*x；sum=1.0；term=1.0；for(i=2；i；i=i+2){ 。
c语言编程，运用余弦定理的该式子，做成一个输入2边及对应角得到第3边的程序。平方根和三角函数的计算 根据题意可得代码如下：includeincludeconst double pi=3.14159265；int main(){double a，b，C，c；printf(\"请输入两边长度及其夹角(角度)：\")；scanf(\"%lf%lf%lf\"，&a，&b，&C)；c=sqrt(a*a+b*b-2*a*b*cos(C*pi/180))；printf(\"第三边的长度为：%f\\n\"，c)；return 0；}
C语言（C++） 自己编写求余弦值的程序。 /*α32313133353236313431303231363533e4b893e5b19e31333332616438=-90，cos(α)=0.877583，my_cos(α)=0.877583α=-75，cos(α)=0.914443，my_cos(α)=0.914443α=-60，cos(α)=0.944957，my_cos(α)=0.944957α=-45，cos(α)=0.968912，my_cos(α)=0.968912α=-30，cos(α)=0.986143，my_cos(α)=0.986143α=-15，cos(α)=0.996530，my_cos(α)=0.996530α=0，cos(α)=1.000000，my_cos(α)=1.000000α=15，cos(α)=0.996530，my_cos(α)=0.996530α=30，cos(α)=0.986143，my_cos(α)=0.986143α=45，cos(α)=0.968912，my_cos(α)=0.968912α=60，cos(α)=0.944957，my_cos(α)=0.944957α=75，cos(α)=0.914443，my_cos(α)=0.914443α=90，cos(α)=0.877583，my_cos(α)=0.877583Press any key to continue123456789101112131415161718192021222324252627282930313233343536#include<；stdio.h>；#include<；math.h>；double my_pow(double x，int n){double result=1.0；int i；for(i=0；i；i)result*=x；return result；}double fact(int n){double result=1.0；int i；for(i=1；i；i)result*=i；return result；}double my_cos(double x){double t=0.0，delta=1.0，cosine=1.0；int。
c语言程序编写：用余弦定理比较三边，然后看是什么三角行， void sort1(float*x，float*y){float d；if(*x<；*y){d=*x；x=*y；y=d；}}main(){float a，b，c，yx；scanf(\"%f%f%f\"，&a，&b，&c)；sort1(&b，&c)；sort1(&a，&b)；sort1(&b，&c)；保证a为最大边*/yx=(a*a-(b*b+c*c))/2；if(yx>；0)printf(\"锐角\")；else if(yx)printf(\"钝角\")；else printf(\"直角\")；printf(\"三角形\\n\")；scanf(\"%d\")；}
编写C语言程序求35度角的正弦余弦正切余切 include<；stdio.h>；#include<；conio.h>；#include<；math.h>；int main(){ double x；x=35；printf(\"余弦值是：\")；printf(\"%f\\n\"，cos(x/180*M_PI))；printf(\"正弦值是：\")；。
C语言编程：使用函数求余弦函数的近似值：输入精度e，用下列公式求cos（x）的近似值 #includeincludeint main(void){double x，e，cosx；double funcos(double e，int x)；printf(\"e：\")；scanf(\"%lf\"，&e)；printf(\"x：\")；scanf(\"%lf\"，&x)；这里是%lfcosx=funcos(e，x)；printf(\"cos(x)=.3f\\n\"，cosx)；return 0；}double funcos(double e，int x){int flag，a，i；double sum，item；double fact(int n)；item=1；这个初始化要大于e，否则不执行下面flag=1；a=0；i=0；sum=0；while(fabs(item)>；=e){item=(flag*pow(x，a))/fact(i)；sum=sum+item；flag=-flag；a=a+2；i=i+2；}return sum；}double fact(int n){int i；double result；result=1；for(i=1；i；i+){result=result*i；}return result；}
